写一个脚本,实现判断192.168.0.0网络里,当前在线的IP有哪些
思路: for循环, 0.1 – 0.254 依次去ping,能通说明在线。
1 2 3 4 5 6 7 8 9 10 11 12
| #!/bin/bash ips="192.168.0." for i in `seq 1 254` do ping -c 2 $ips$i >/dev/null 2>/dev/null if [ $? == 0 ] then echo "echo $ips$i is online" else echo "echo $ips$i is not online" fi done
|
也可以使用 nmap 命令,速度比较快一点
1 2 3 4 5 6 7 8 9 10 11 12 13 14
| #!/bin/bash myyum () { if ! rpm -qa|grep -q "^$1" then yum install -y "^$1" else echo $1 already installed. fi } for i in nmap do myyum $i done nmap -sP 192.168.0.0/24
|